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Find the equation of the tangent and normal lines to 4x^3+3y=5x^3 +6y^2
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1 vote
Find the equation of the tangent and normal lines to 4x^3+3y=5x^3 +6y^2

User Radek Simko
by
7.3k points

1 Answer

1 vote
64x + 3y = 125x + 36y
3y - 36y = 125x - 64x
- 33y = 61x
y = 1.6x
User Ashelyn Dawn
by
7.6k points
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