menu
QAmmunity.org
Login
Register
My account
Edit my Profile
Private messages
My favorites
Register
Ask a Question
Questions
Unanswered
Tags
Categories
Ask a Question
When two balanced dice are rolled, the sum of the dice can be 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, or 12, giving 11 possibilities. therefore the probability is 1/11 that the sum is 12?
asked
Jun 5, 2019
31.4k
views
5
votes
When two balanced dice are rolled, the sum of the dice can be 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, or 12, giving 11 possibilities. therefore the probability is 1/11 that the sum is 12?
Mathematics
college
John Blackbourn
asked
by
John Blackbourn
5.8k
points
answer
comment
share this
share
0 Comments
Please
log in
or
register
to add a comment.
Please
log in
or
register
to answer this question.
1
Answer
0
votes
False.
There are 36 possible outcomes, corresponding to numbers 1-6 independently appearing on each of the dice. Only one of those outcomes is double-sixes, resulting in a sum of 12. The probability that the sum is 12 is 1/36.
In short, the 11 outcomes listed in your problem statement are not equally-likely.
Dsingleton
answered
Jun 11, 2019
by
Dsingleton
5.6k
points
ask related question
comment
share this
0 Comments
Please
log in
or
register
to add a comment.
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.
6.5m
questions
8.7m
answers
Other Questions
What is the least common denominator of the four fractions 20 7/10 20 3/4 18 9/10 20 18/25
What is 0.12 expressed as a fraction in simplest form
What is the initial value and what does it represent? $4, the cost per item $4, the cost of the catalog $6, the cost per item $6, the cost of the catalog?
What is distributive property ?
What is the measure of xyz
Twitter
WhatsApp
Facebook
Reddit
LinkedIn
Email
Link Copied!
Copy
Search QAmmunity.org