Question

Aluminum foil is often incorrectly termed tin foil. If the density of tin is 7.28g/cm³,what is the thickness of a piece of tin foil that measures 5.70cm by 4.25cm and has a mass of 0.655g

Answer 1

The thickness of the piece of foil is
`3.71*10^(-3)cm`

Step-by-step explanation:

Please see the figure below that represents the aluminum foil. The volume of the tin foil will be:

V = length * width * thickness

Now, the density of tin is given by the expression:

ρ =
`(m)/(V)`

where m is the mass of the tin and V is the volume of it.

From the expression for the density we have:

V = m/ρ

And replacing the expression for the Volume of the tin, we have:

length*width*thickness = m/ρ

so

thickness = m/(ρ*length*width)

And replacing the given values we have:

`thickness=(0.655g)/(7.28(g)/(cm^(3))*5.70cm*4.25cm)`

`thickness=(0.655g)/(176,358(g)/(cm))`

`thickness=3.71*10^(-3)cm`