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(3 -1) y=1/3x-3 write an equation of the line that passes through the given point and is parallel to the given line

User Ajeh
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1 Answer

7 votes

Answer:


y = 1/3x-2

Explanation:

General line equation:


(y-y_(1))/(x-x_(1)) = (y_(2)-y_(1))/(x_(2)-x_(1))\\

Or


y = a.x + b\\a = (y_(2)-y_(1))/(x_(2)-x_(1))\\b = y_(1) - a.x_(1)

where a is the slope and b is vertical displacement.

For a line to be parallel to another, they both have to have the same slope, therefor, the parallel line's slope is 1/3.

By substituting the given point and a = 1/3 in above equation for b, b is equal to -2. Therefore,


y = 1/3x - 2

User ALoR
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