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The Reel Good Cinema is conducting a mathematical study. In its theater, there are 200 seats. Adult tickets cost $12.50 and child tickets cost $6.25. The cinema's goal is to sell at least $1500 worth of tickets for the theater.

User Greg Smith
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2 Answers

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If the goal is to sell at least $1500 worth of tickets then what you can do is add the 12.50+ 6.25 which well equal 18.75. Then you can divide 1500/18.75 which eqauls to 80 meaning at least 80 seats must be sold
User Sprocket
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To reach the cinema's goal of selling at least $1500 worth of tickets in a theater with 200 seats, there are several possible combinations of adult and child tickets. One combination that satisfies the revenue requirement is 150 adult tickets and 20 child tickets, resulting in a total revenue of $1900.

The cinema wants to sell at least $1500 worth of tickets. Let's assume the number of adult tickets sold is A, and the number of child tickets sold is C. The cost of 1 adult ticket is $12.50, so the total revenue from adult tickets is 12.50A. The cost of 1 child ticket is $6.25, so the total revenue from child tickets is 6.25C. The total revenue from ticket sales must be at least $1500, so 12.50A + 6.25C >= 1500.

Considering that the cinema has 200 seats, the maximum number of adult tickets sold is 200, and the maximum number of child tickets sold is also 200.

We can create a table to find the possible combinations that satisfy the revenue requirement:

Adult Tickets (A) Child Tickets (C) Total Revenue (12.50A + 6.25C)

200 0 $2500

150 20 $1900

100 40 $1300

50 60 $700

0 80 $100

The combination of 150 adult tickets and 20 child tickets would satisfy the revenue requirement, with a total revenue of $1900.

User Kris Braun
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