To reach the cinema's goal of selling at least $1500 worth of tickets in a theater with 200 seats, there are several possible combinations of adult and child tickets. One combination that satisfies the revenue requirement is 150 adult tickets and 20 child tickets, resulting in a total revenue of $1900.
The cinema wants to sell at least $1500 worth of tickets. Let's assume the number of adult tickets sold is A, and the number of child tickets sold is C. The cost of 1 adult ticket is $12.50, so the total revenue from adult tickets is 12.50A. The cost of 1 child ticket is $6.25, so the total revenue from child tickets is 6.25C. The total revenue from ticket sales must be at least $1500, so 12.50A + 6.25C >= 1500.
Considering that the cinema has 200 seats, the maximum number of adult tickets sold is 200, and the maximum number of child tickets sold is also 200.
We can create a table to find the possible combinations that satisfy the revenue requirement:
Adult Tickets (A) Child Tickets (C) Total Revenue (12.50A + 6.25C)
200 0 $2500
150 20 $1900
100 40 $1300
50 60 $700
0 80 $100
The combination of 150 adult tickets and 20 child tickets would satisfy the revenue requirement, with a total revenue of $1900.