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What is the period of the function f(x)=cos2x

1/2

π/2

π

2

User Manzapanza
by
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2 Answers

5 votes

Answer:


\displaystyle \pi

Explanation:


\displaystyle f(x) = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow (C)/(B) \\ Wavelength\:[Period] \hookrightarrow (2)/(B)\pi \\ Amplitude \hookrightarrow |A|

Accourding to the above information, you will have this result:


\displaystyle \boxed{\pi} = (2)/(2)\pi

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User Aeldron
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8.9k points
1 vote

Answer:

π

Explanation:

General form of the cosine function is:


y(x)=Acos(\omega x +\phi)

Where:


A= Amplitude\hspace{3} of \hspace{3} the\hspace{3} function\\\omega=Angular\hspace{3} frequency\\\phi=Phase\hspace{3} shift

The frequency of the function is given by the following equation:


f=(\omega)/(2 \pi)

The period is the reciprocal of the frequency, so:


T=(1)/(f) =(2 \pi)/(\omega)

From the equation provided, you can see that the angular frequency is 2. Therefore, the periodof the function is:


T=(2 \pi)/(\omega) =(2\pi)/(2) =\pi

User Cherif
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