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What is the maximal domain on the function x^2+8/x^2+4x-5?

User MonteCarloSims
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1 Answer

20 votes
20 votes

Answer:

{x ∈ R: x ≠ -5 and x ≠ 1}.

Explanation:

x^2+8/x^2+4x-5

= x^2+8 / (x - 1)(x + 5)

The denominator is zero when x = 1 or x = -5

So:

Domain is:

{x ∈ R : x ≠ -5 and x ≠ 1}.

User Soitje
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