Question

What is the missing term? (10x – 4x2) – (7x + ?) = 3x – 6x2

Answer 1

10x-4x^2-7x-a=3x-6x^2
3x-4x^2-a=3x-6x^2
a=6x^2-4x^2
a=2x^2

Answer 2

Let the missing number be a.

Given that:

`(10x-4x^2)-(7x+a) = 3x-6x^2`

Remove the parenthesis we have;

`10x-4x^2-7x-a= 3x-6x^2`

Combine like terms we have;

`3x-4x^2-a= 3x-6x^2`

Subtract 3x from both sides we have;

`-4x^2-a=-6x^2`

Add
`4x^2` to both sides we have;

`-a=-6x^2+4x^2`

Simplify:

`-a=-2x^2`

Divide both sides by -1 we have;

`a=2x^2`

Therefore, the missing term is,
`2x^2`