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What is the graph of the system y = −2x + 3 and 2x + 4y = 8?

A. line through point (0, 3) and (1, 1). Line through (0, negative 2) and (negative 4, 0)
B. line through point (0, 3) and (1, 1). Line through (0, 2) and (negative 4, 0)
C. line through point (0, 3) and (1, 1). Line through (0, 2) and (4, 0)
D. line through point (0, 3) and (1, 1). Line through (0, negative 2) and (4, 0)

2 Answers

5 votes
You answer is:
Line through point (0,3) and (-1,1). Line through (0,2) and (4,0)
The one that resembles this the most is letter C
User Sangeet Suresh
by
5.8k points
4 votes

Answer:

The line passing through points (0,3) and (1.5,0) . Line through (0,2) and (4,0).

Explanation:

We are given that two equations


y=-2x+3...(I equation )


2x+4y=8....(II equation)

We have to find the the graph of the given system

We solve first I equation

Substitute x=0 in equation I then we get


y=3

Now, we substituting y= 0 then we get


0=-2x+3


2x=3


x=(3)/(2)=1.5


x=1.5

Hence, the line
y=-2x+3 passing through the points (0,3) and (1.5,0).

We are solving equation II

Substitute x= 0 in II equation

Then we get
4y=8


y=(8)/(4)=2


y=2

Now, we substituting y=0 then we get


2x=8


x=(8)/(2)


x=4

Therefore, the equation
2x+4y=8 is passing through the points (0,2) and (4,0).

But any option does not match.

What is the graph of the system y = −2x + 3 and 2x + 4y = 8? A. line through point-example-1
User Marcosdsanchez
by
6.1k points