Question

What is the total displacement???

Answer 1

Displacement (between time 0 and time 25) is the area under the velocity time curve, i.e. ∫ vdt.
Here, v(0)=10, v(25)=34 (approx.)
Therefore
displacement = (1/2)(10+34 m/s)*(25-0) s [ trapezoid area ]
=550 m

Answer 2

Answer: 562.5 m

`Displacement = velocity * time`= area under the curve in velocity-time graph

The area of the quadrilateral formed by the graph is given by:

`A=((a+b))/(2) h`

where, a and b are two parallel sides of the quadrilateral, h is the perpendicular distance between the two parallel sides.

from the given graph,

`a=10 m/s`

`b=35 m/s`

`h=25 s`

Hence,
`A= ((10+35) m/s)/(2)* 25 s=562.5 m`

The area under graph = 562.5 m. Hence, the total displacement is 562.5 m.