Question

A 12.41 g sample of nabr contains 22.34% na by mass. considering the law of constant composition (definite proportions) how many grams of sodium does a 8.99 g sample of sodium bromide contain?

Answer 1

I'm assuming you mean how many grams of sodium does 8.99 grams of sodium bromide have, because Bromine would not have any sodium in it.

Then, just direct calculate 22.34

`(22.34 / 100) * 8.99 = 2.008366`

Answer 2

`m_(Na)=2.01g`

Step-by-step explanation:

Hello,

In this case, given the by mass percent of sodium in sodium bromide::

`\% Na=(m_(Na))/(m_(NaBr))*100\%=22.34 \%`

Solving for the mass of sodium, considering the constant composition of sodium in the sodium bromide, we obtain:

`m_(Na)=(\% Na*m_(NaBr))/(100\%) =(22.34\%*8.99g)/(100\%) \\\\m_(Na)=2.01g`

Best regards.