Question

Pythagorean theorem 12^2 +b^2=27^2

Answer 1

Solve for b over the real numbers:
b^2 + 12^2 = 27^2
b^2 + 12^2 = b^2 + 144 and 27^2 = 729:
b^2 + 144 = 729

Subtract 144 from both sides:
b^2 = 585
Take the square root of both sides:
Answer: b = 3 sqrt(65) or b = -3 sqrt(65)