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a Special Olympics event has 14 more boys than girls competing the total number of participants is 1000 how many boys competed and how many girls competed

2 Answers

3 votes
girls=x
boys=x+14
x+x+14=1000
2x+14=1000
2x=1000-14
2x=986
x=493
girls=x=493
boys=x+14=493+14=507
User Nasi
by
8.4k points
2 votes

Answer:

493 girls and 507 boys competed.

Explanation:

Let x represent number of girls.

We have been given that a Special Olympics event has 14 more boys than girls competing. So the number of boys would be
x+14.

We are also told that the total number of participants is 1000. We can represent this information in an equation as:


x+x+14=1000


2x+14=1000


2x+14-14=1000-14


2x=986


(2x)/(2)=(986)/(2)


x=493

Therefore, 493 girls competed in the Olympics.

Number of boys:
x+14\Rightarrow 493+14=507

Therefore, 507 boys competed in the Olympics.

User Jeff Evans
by
8.5k points
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