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15 votes
15 votes
Augustina has 2 posters with length x inches.

One poster has a width of x + 5 inches, and
the other has a width of x + 7 inches. Write an
expression to represent the area of wall that the
posters will cover.

Augustina has 2 posters with length x inches. One poster has a width of x + 5 inches-example-1
User Ean V
by
2.4k points

2 Answers

11 votes
11 votes

Answer:

2x² + 12x

Explanation:

Area of rectangle:

Area of rectangle = length * width

Poster 1:

length = x inches

widht = (x + 5) inches

Area of poster 1 = x * (x + 5)

= x*x + x*5 {Distributive property}

= x² + 5x square inches

Poster 2:

length = x inches

width = (x + 7) inches

Area of poster =x *(x+ 7)

= x*x + x*7

= x² + 7x

Area of wall = area of poster1 + area of poster 2

= x²+ 5x + x² + 7x

= x² + x² + 5x + 7x {Combine like terms}

= 2x² + 12x

User BrianK
by
2.9k points
16 votes
16 votes

Answer:


2x^2+12x

Explanation:

Dimensions of Poster 1:

  • Length = x inches
  • Width = (x + 5) inches

Dimensions of Poster 2:

  • Length = x inches
  • Width = (x + 7) inches

The posters can be modeled as rectangles.


\boxed{\textsf{Area of a rectangle}=\sf length * width}

Therefore, the expressions for the area of each poster are:


\implies \textsf{Area of Poster 1}=x(x+5)


\implies \textsf{Area of Poster 2}=x(x+7)

Therefore, the expression that represents the area of the wall that the posters will cover is the sum of the expressions of the areas of the individual posters:


\begin{aligned}\textsf{Area of wall posters will cover}&=\textsf{Area of Poster 1}+\textsf{Area of Poster 2}\\& = x(x+5)+x(x+7)\\&=x^2+5x+x^2+7x\\&=x^2+x^2+5x+7x\\&=2x^2+12x\end{aligned}

User Guyaloni
by
2.8k points