Question

If 10 KJ of thermal energy is added to the system and 10 KJ of work is done by the system, what happens to the internal energy?

Answer 1

Given :

• Thermal energy = 10 KJ
• Work done = 10 KJ

Solution :

We need to calculate the internal energy of the system i.e., ΔU.

• Thermal energy (ΔQ) = 10 KJ

We know that,

• ΔU = ΔQ - ΔW

>> ΔU = (10 - 10) KJ

>> ΔU = 0

Therefore,

• Change in internal energy of system is zero.