Question

How can one fifthx − 2 = one thirdx + 8 be set up as a system of equations?

A) 5y - 5x =10
3y - 3x =24

B ) 5y - 5x = -10
3y + 3x =24

C) 5y + x = -10
3y + x =24

D) 5y - x = -10
3y - x =24

Answer 1

C.5y+x=-10                                                                                                             3y+x=24                                                                                                                i hope that help 

Answer 2

System of linear equations:

`5y-x=-10`

`3y-x=24`

D is correct

Explanation:

Given:
`(1)/(5)x-2=(1)/(3)x+8`

It is complex linear equation. To solve this linear equation using graph by making system of linear equation.

Left side equation makes one equation and right side makes another.

Equation 1:

`y=(1)/(5)x-2`

Now change into standard form of line

`ax+by=c`

`5y-x=-10`

Equation 2:

`y=(1)/(3)x+8`

Now change into standard form of line

`ax+by=c`

`3y-x=24`

System of linear equations:

`5y-x=-10`

`3y-x=24`