105k views
4 votes
what is the most precise name for quadrilateral abcd with vertices a(-5, -1) b(-5, 3) c(-2, 3) d(-2, -1)

what is the most precise name for quadrilateral abcd with vertices a(-5, -1) b(-5, 3) c-example-1

2 Answers

6 votes
check the picture below.

is a parallelogram, it has two pairs of sides that are parallel.

hmmm is not a square, since is a 3x4, so all sides aren't equal.

is a quadrilateral, it has four sides alright.

though is not a square, it does have 4 right-angles at its corners... that means that is a rectangle, besides being a parallelogram.
what is the most precise name for quadrilateral abcd with vertices a(-5, -1) b(-5, 3) c-example-1
User Mjfgates
by
7.5k points
6 votes

Answer:

1st Option is correct.

Explanation:

Given:

Vertices of the quadrilateral ABCD.

A( -5 , -1 ) , B( -5 , 3 ) , C( -2 , 3 ) , D( -2 , -1 )

To find: Name of the Quadrilateral.

We use Distance formula to find the length of the sides and diagonal of the Quadrilateral.

Distance between two point =
√((x_2-x_1)^2+(y_2-y_1)^2)

Length of Side AB
=√((-5-(-5))^2+(-1-3)^2)=√((0)^2+(-4)^2)=√(0+16)=4

Length of Side CB
=√((-2-(-5))^2+(3-3)^2)=√((-2+5)^2+(0)^2)=√(9+0)=3

Length of Side CD
=√((-2-(-2))^2+(-1-3)^2)=√((0)^2+(-4)^2)=√(0+16)=4

Length of Side AD
=√((-2-(-5))^2+(-1-(-1))^2)=√((3)^2+(0)^2)=√(9+0)=3

Length of the Diagonal AC
=√((-2-(-5))^2+(3-(-1))^2)=√((3)^2+(4)^2)=√(9+16)=5

Length of the Diagonal BD
=√((-2-(-5))^2+(-1-3)^2)=√((3)^2+(-4)^2)=√(9+16)=5

So, Opposite side of the Quadrilateral are Equal that is AB = CD = 4 unit and CB = AD = 3 unit

Also, Diagonals are equal that is AC = BD = 5 unit

Quadrilateral is a RECTANGLE.

Therefore, 1st Option is correct.

User Chamod Pathirana
by
7.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories