Question

Which missing item would complete this beta decay reaction?
 PLATO

Answer 1

Answer:
`_(-1)^0\beta`

Explanation:

General representation of an element is given as:
`_Z^A\textrm{X}`

where,

Z represents Atomic number

A represents Mass number

X represents the symbol of an element

Beta decay : In this process, a neutron gets converted into a proton and an electron releasing a beta-particle. The beta particle released carries a charge of -1 units.

`_Z^A\textrm{X}\rightarrow _(Z+1)^A\textrm{Y}+_(-1)^0\beta`

The given reaction would be represented as:

`_(43)^(98)\textrm{Tc}\rightarrow_(44)^(98)\textrm{Pb}+_(-1)^0\beta`

Answer 2

Answer: Option (a) is the correct answer.

Step-by-step explanation:

The high energy electrons are known as beta particles. Charge on a beta particle is -1, that is, similar to the charge present in an electron.

Hence, symbol that represents a beta particle is
`^(0)_(-1)\beta`.

For example,
`^(98)_(43)Tc \rightarrow ^(98)_(44)Ru + ^(0)_(-1)\beta`

This reaction is a radioactive decay rection when
`^(98)_(43)Tc` on decaying gives
`^(98)_(44)Ru`along with emission of a beta particle.

Whereas
`^(4)_(2)He` is an alpha particle,
`^(0)_(0)\gamma` is a gamma particle, and
`^(1)_(0)n` is a neutron.

Thus, we can conclude that the particle
`^(0)_(-1)\beta` would complete this given beta decay reaction.