Question

Solve for x .-.


`\tt {x}^(2) + 9 = 298`
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Answer 1

Collect the like terms
X^2=298-9
X^2=289
To find x
Square root both side

Square root of x^2 =square root of 289
Will remain
X=plus or minus 17 cos you are looking for 2 answers

Answer 2

x = 17

Explanation:

Solving for 'x':

x² + 9 = 298

Subtract 9 from both sides,

x² + 9 - 9 = 298 - 9

x² = 289

Prime factorize 289,

x² = 17*17

Take square root,

`\sf √(x^2)= √(17*17)`

x = 17