Question

What element forms an ion with an electronic configuration of 1s22s22p63s23p63d104s24p64d105s25p6 (or [xe]) and a –2 charge?

Answer 1

Step-by-step explanation:

Atomic number of Xenon is 54 and its electronic configuration is
`1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)3d^(10)4s^(2)4p^(6)4d^(10)5s^(2)5p^(6)`.

When an element gains an electron then it acquires a charge of -1. And, when two electrons are gained by an element then it acquires a charge of -2 and so on.

Tellurium is the element which has 52 electrons and electronic configuration of
`Te^(2-)` is as follows.
`1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)3d^(10)4s^(2)4p^(6)4d^(10)5s^(2)5p^(6)`

Thus, we can conclude that tellurium element forms an ion with an electronic configuration of
`1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)3d^(10)4s^(2)4p^(6)4d^(10)5s^(2)5p^(6)` and a charge of -2.

Answer 2

The appropriate response would be Tellurium. For the reason that it can receive a - 2 charge, and when it grabs two electrons, it fills the 5p shell with six electrons, so it will have the electronic arrangement of [Xe]. It cannot be Barium since if it loses two electrons, it will get the electronic configuration of [Xe] when it loses the 6s2 electrons, but it will be a +2 cation, not an anion.