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During this reaction, p4 + 5o2 → p4o10, 0.800 moles of product was made in 15.0 seconds. what is the rate of reaction? 56.8 g/min 227 g/min 908 g/min 13,600 g/min
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During this reaction, p4 + 5o2 → p4o10, 0.800 moles of product was made in 15.0 seconds. what is the rate of reaction? 56.8 g/min 227 g/min 908 g/min 13,600 g/min

User Yuyichao
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2 Answers

3 votes

Answer:

908 g/min

Step-by-step explanation:

User Forkmohit
by
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4 votes
The solution for this problem would be:
The mass of P4O10 is computed by: 0.800 mol x 284 g/mol = 227g t = 15.0 s ( 1 min / 60 s) = 0.25 min
So solving for the rate will be mass over t = m/t = 227/0.25 = 908 g/min would be the answer for this problem.
User Shurmajee
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