Answer : The solubility of
is, 0.19 mole/L
Explanation :
The formula used for henry's law is:

where,
= solubility of
= ?
= partial pressure of
= 5.6 atm
= Henry's law constant =

Now put all the given values in the above formula, we get:


Therefore, the solubility of
is, 0.19 mole/L