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If s^2– 4s – 6 = 6, What are the possible values of s?

1 Answer

9 votes

Answer:

s = +6 or -2

Explanation:


{s}^(2) - 4s - 6 = 6


= > {s}^(2) - 4s - 6 - 6 = 0


= > {s}^(2) - 4s - 12 = 0

Lets factorise the eqn.


= > {s}^(2) - 6s + 2s - 12 = 0


= > s(s - 6) + 2(s - 6) = 0


= > (s - 6)(s + 2) = 0

Here 's' will have 2 values.

1)
s - 6 = 0


= > s = 6

2)
s + 2 = 0


= > s = - 2

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