Question

A vertical spring 0.100 meter long is elongated to a length of -.119 meter when a 1.00 kilogram mass is attached to the bottom of the spring. the spring constant of this spring is

Answer 1

By definition we have that the force of the spring is given by:
F = -k * deltax
Where,
k: spring constant
deltax = elongation
Let's clear k:
k = -F / delta x
k = mg / delta x
delta x = 0.119 -0.1 = 0.019m
Substituting the values:
k = (1) * (9.81) / (. 019)
k = 516 N / m
Answer:
the spring constant of this spring is
k = 516 N / m