Question

An amoeba has 1.00 x10^6 protons and a net charge of 0.300 pc. how many fewer electrons are there than protons

Answer 1

`N_1 = 8.75 * 10^5`

Step-by-step explanation:

Net charge on amoeba is given as

`Q = 0.300 pC`

also we know that

`1 pC = 10^(-12)C`

now we know that

`Q = 0.300 * 10^(-12) C`

here we know by the quantization of charge

`Q = (N + N_1)e`

`0.3 * 10^(-12) = ((1.00 * 10^6) + N_1)(1.6 * 10^(-19))`

now we have

`1.87 * 10^6 = 1.00 * 10^6 + N_1`

`N_1 = 8.75 * 10^5`

Answer 2

1 pico anything = 1 * 10^-12
0.300 pico coulombs = 0.300 * 10^-12 coulombs = 3.00 * 10^-13 coulombs.

1 proton has a charge of 1.60 * 10^-19 c
1*10^6 protons have a charge of 1.6 * 10^-19 * 1*10^6
Gross Charge of protons = 1.6 * 10^-13 c

That's what the charge should be if only protons were present.
However there are electrons around and when they are taken into consideration, the charge drops to 3.00 * 10^-13

So the difference allows us to calculate the number of electrons. The way the question is worded, this is impossible. Sorry.