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Factor completely. 49 t6 - 4 k8

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asked Feb 10, 2019 126k views

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Factor completely. 49 t6 - 4 k8

Mathematics
college

Sarita asked

by Sarita

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49 t^6 - 4 k^8
= (7t^3)^2 - (2k^4)^2
= (7t^3 + 2k^4)(7t^3 - 2k^4)

Lakshmaji answered Feb 17, 2019

by Lakshmaji

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Factor completely. 49 t6 - 4 k8

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