Question

If 56 grams of carbon monoxide burns in oxygen to produce 88 grams of carbon dioxide, the mass of oxygen involved in the reaction is_____ grams. 32 56 88 144

Answer 1

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Step-by-step explanation:

Answer 2

Answer : The mass of oxygen involved in the reaction is, 32 grams.

Explanation : Given,

Mass of carbon monoxide = 56 g

Mass of carbon dioxide = 88 g

Molar mass of carbon monoxide
`(CO)` = 28 g/mole

Molar mass of oxygen
`(O_2)` = 32 g/mole

First we have to calculate the moles of carbon monoxide.

`\text{Moles of CO}=\frac{\text{Mass of CO}}{\text{Molar mass of CO}}=(56g)/(28g/mole)=2moles`

Now we have to calculate the moles of oxygen gas.

The balanced chemical reaction will be,

`2CO+O_2\rightarrow 3CO_2`

From the balanced chemical reaction, we conclude that

2 moles of CO react with 1 mole of
`O_2`

So, the moles of
`O_2` = 1 mole

Now we have to calculate the mass of oxygen.

`\text{Mass of }O_2=\text{Moles of }O_2* \text{Molar mass of }O_2`

`\text{Mass of }O_2=1mole* 32g/mole=32g`

Therefore, the mass of oxygen involved in the reaction is, 32 grams.