Question

A gas has an initial volume of 168 cm3 at a temperature of 255 K and a pressure of 1.6 atm. The pressure of the gas decreases to 1.3 atm, and the temperature of the gas increases to 285 K. What is the final volume of the gas?

Answer 1

i wrote the answer on this paper and here is the calculations step by step

very sry the "V" must be replaced with 285 and the 285 must be replaced with "V" and the answer is 231.09 cm3. sorry for the inconvenience.

Answer 2

Answer: The volume when the pressure and temperature has changed is
`231.1cm^3`

Step-by-step explanation:

To calculate the volume when temperature and pressure has changed, we use the equation given by combined gas law. The equation follows:

`(P_1V_1)/(T_1)=(P_2V_2)/(T_2)`

where,

`P_1,V_1\text{ and }T_1` are the initial pressure, volume and temperature of the gas

`P_2,V_2\text{ and }T_2` are the final pressure, volume and temperature of the gas

We are given:

`P_1=1.6atm\\V_1=168cm^3\\T_1=255K\\P_2=1.3atm\\V_2=?cm^3\\T_2=285K`

Putting values in above equation, we get:

`(1.6atm* 168cm^3)/(255K)=(1.3atm* V_2)/(285K)\\\\V_2=231.1cm^3`

Hence, the volume when the pressure and temperature has changed is
`231.1cm^3`