Given: 10g^2+33g=9-2g^2
Group the q^2 terms first, then the q terms, and finally the constants:
12g^2 + 33q - 9 = 0. Make sure you agree with this, or otherwise fix it.
Tools for solving quadratic equations include the following and more:
graphing
quadratic formula
completing the square
I've graphed this simplified quadratic on my TI-83 calculator and see that -3 seems to be a root. Let's check it!
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-3 / 12 33 -9
-36 9
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12 -3 0 Since the remainder is zero, -3 is a root and (x+3) is a factor. The other factors are 3 and (4x -1)
Then 3(4g-1)(g+3) = 0, with the result that g = 1/4 and g = -3.
Please check these roots by subst. into the original equation.