Question

PLEASE HELP FAST!!!!

Given cos A = 0.42, find angle A in degrees. Round your answer to the nearest hundredth.
65.17 degrees
22.78 degrees
114.83 degrees
24.83 degrees

Find the arc length with the given information.
Central angle = 3.14/4, radius = 6 (3.14 = pie)
3.14/24
2(3.14)/3
3(3.14)/4
3(3.14)/2

Which angle has its terminal side in the third quadrant?
3(3.14)/4
3.14/3
5(3.14)/3
7(3.14)/6

Determine the quadrant for an angle with the following characteristics: sin(theta) < 0 and tan(theta)<0
Quadrant I
Quadrant II
Quadrant III
Quadrant IV

Answer 1

Please, no more than 1 or 2 questions per post.
The questions you've posted are important and will show up in your further studies of math.

If cos A = 0.42, find the angle A in degrees.

If you use a calculator, the calculator will probably express the angle in radians, not in degrees: arccos 0.42 = 1.137 radians.

Now convert 1.137 radians to degrees as follows:

1.137 rad 180 deg
-------------- * -------------- = 65.17 degrees
1 π rad

Answer 2

Explanation:

1) Cos A =0.42

A = arc cos 0.42 = 65.17 degrees

Option A

2) Central angle = pi/4 gives arc length = 1/8 perimeter

= 2(3.14)(6)/8 = 3(3.14)/2

Option d

3) III quadrant angles are between pi and 3pi/2

Hence we have 5pi/3 Option C

4) sin theta and tan theta negative gives

quadrant III is the right answer.