Question

The length of the base of a square pyramid is 9 inches the slant height is 12 inches what is the surface area of the pyramid

Answer 1

The surface area is
`297\ in^(2)`

Explanation:

we know that

The surface area of the square pyramid is equal to the area of the square base plus the area of its four lateral triangular faces

so

`SA=b^(2)+4[(1)/(2)(b)(l)]`

where

`b=9\ in`

`l=12\ in` -----> the slant height

substitute the values

`SA=9^(2)+4[(1)/(2)(9)(12)]`

`SA=297\ in^(2)`