Answer:
B.
Explanation:
First, we need to compare vertices from the original figure and the transformed one.

You can observe that coordinates where changed of position. Also, the vertical coordinate of the transformed figure has opposite sign.
In other words, the transformation follows the rule


However, notice that the coordinates are not the same as the given transformation. That is because the second transformation applied was a reflection accros the x-axis which follows the rule

Applying the rule, we have

Which are congruent with the given transformed coordinates.
Therefore, the transformations are a 90° rotation counterclockwise and a reflection accros the x-axis. The right answer is B.