Question

How many moles is 4.17x10^23 atoms of CaCI2? HELP PLS !!

Answer 1

0.692 mol CaCl₂

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Chemistry

Atomic Structure

• Reading a Periodic Table
• Using Dimensional Analysis
• Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Step-by-step explanation:

Step 1: Define

4.17 × 10²³ atoms CaCl₂

Step 2: Identify Conversions

Avogadro's Number

Step 3: Convert

1. Set up:
   `\displaystyle 4.17 \cdot 10^(23) \ atoms \ CaCl_2((1 \ mol \ CaCl_2)/(6.022 \cdot 10^(23) \ atoms \ CaCl_2))`
2. Multiply/Divide:
   `\displaystyle 0.692461 \ mol \ CaCl_2`

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

0.692461 mol CaCl₂ ≈ 0.692 mol CaCl₂