Question

You use an inclined plane to move furniture into a truck. You perform 352 kj of work, but only do 229 kj of useful work. What is the efficiency of the inclined plane?

Answer 1

Answer: 65.05%

Explanation: using

efficiency = (useful work/work done)×100

= (229/352)×100

= 65.05%

Answer 2

The efficiency of the inclined plane is 65.05%.

Step-by-step explanation:

It is given that, you use an inclined plane to move furniture into a truck.

Work done performed by the person, i.e. input work
`W_i=352\ kJ`

Useful work done by the person, i.e. input work
`W_o=229\ kJ`

The efficiency of any simple machine is always less than 1. For the inclined plane it is given by :

`\eta=(W_o)/(W_i)* 100`

`\eta=(229\ kJ)/(352\ kJ)* 100`

`\eta=65.05\%`

So, the efficiency of the inclined plane is 65.05%. Hence, this is the required solution.