Question

Consider the reaction. mc033-1.jpg At equilibrium, the concentrations are as follows. [NOCl] = 1.4 ´ 10–2 M [NO] = 1.2 ´ 10–3 M [Cl2] = 2.2 ´ 10–3 M What is the value of Keq for the reaction expressed in scientific notation? 1.6 ´ 10–5 6.2 ´ 10–4 6.2 ´ 104 1.6 ´ 105

Answer 1

Answer:
`1.6* 10^(-5)`

Explanation: Equilibrium constant is the ratio of product of concentration of products to the product of concentration of reactants each term raised to their stochiometric coefficients.

`2NOCI(g)\rightleftharpoons 2NO(g) +CI_2(g).`

Given :

`[NOCl]=1.4* 10^(-2)M`.

`[NO]=1.2* 10^(-3)M`.

`[Cl_2]=2.2* 10^(-3)M`.

`K=([NO]^2[Cl_2])/([NOCl]^2)`

`K=([1.4* 10^(-2)]^2[1.2* 10^(-3)])/([2.2* 10^(-3)]^2)`

`K=1.6* 10^(-5)`

Answer 2

Answer is:value of Keq for the reaction is 1,6·10⁻⁵.
Chemical reaction: 2NOCI(g) ⇄ 2NO(g) + CI₂(g).
[NOCl] = 1,4·10⁻² M.
[NO] = 1,2·10⁻³ M.
[Cl₂] = 2,2·10⁻³ M.
K = [NO]² · [Cl₂] ÷ [NOCl]².
K = (1,2·10⁻³ M)² · 2,2·10⁻³ M ÷ (1,4·10⁻² M)².
K = 1,6·10⁻⁵.