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What is the value of log

{16}^(4)
(1 point)​

User Psilocybin
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65,536 I believe is the answer
User Simlev
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9514 1404 393

Answer:

4·log(16) = 16·log(2) ≈ 4.81648

Explanation:

The rules of logarithms are ...

log(a^b) = b·log(a)

Here, we have ...

log(16^4) = 4·log(16)

However, we recognize that 16 = 2^4, so this becomes ...

log(16^4) = 4·(log(2^4)) = 4·4·log(2) = 16·log(2)

The base-10 logarithm of 2 is about 0.30103, so this is ...

log(16^4) ≈ 16·0.30103 = 4.81648

Choose the form of the answer you need:

log(16^4) = 4·log(16) = 16·log(2) ≈ 4.81648

User Cabad
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