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What are the solutions to the equation? p2−12p=13

1 Answer

4 votes

Answer:

The solutions of the given equations are -1 and 13.

Explanation:

The given equation is


p^2-12p=13

Subtract 13 from both the sides.


p^2-12p-13=0

Middle term can be written as -13p+p,


p^2-13p+p-13=0


p(p-13)+1(p-13)=0


(p+1)(p-13)=0

Using zero product property, equal each factor equal to 0.


p+1=0\Rightarrow p=-1


p-13=0\Rightarrow p=13

Therefore the solutions of the given equations are -1 and 13.

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