Question

A 2650-lb car is traveling at sea level at a constant speed. its engine is running at 4500 rev/min and is producing 175 ft-lb of torque. it has a drivetrain efficiency of 90%, a drive axle slippage of 2%, 15- inch–radius wheels, and an overall gear reduction ratio of 3 to 1. if the car's frontal area is 21.5 ft 2 , what is its drag coefficient?

Answer 1

the drag coefficient is given by
C =( (F - fW) * 2 ) / ( A*V*V*r)
V = speed of the vehicle = 192.42
f = cofficient of rolling resistance = 0.0231
F = traffic effort = 378
r = density of air = 0.002378
A = frontal area of the vehicle = 21.5
W = weight of the vehicle = 2650
by substituting all the values in the above equation
drag coefficient = C = 0.167

Answer 2

Check the attached file for the answer.