From the periodic table, we know that 1 mole of Krypton has a molar mass of 83.798 grams/mole.
So 10 grams would have (10/83.798) which is 0.1193345903 moles.
If we multiply this by Avogadro's number, we get the amount of Krypton atoms in 10 grams.
0.1193345903 x 6.02 x 10^23 = 7.184 x 10^22 atoms
Accounting for significant figures, the answer would be: 7 x 10^22 atoms