128k views
3 votes
Subtract. (x^2+43x+10)−(−10x^2−5x+10) Express the answer in standard form. Enter your answer in the box.

2 Answers

5 votes
(x^2 + 43x +10) - (−10x^2−5x+10)
x^2 + 43x +10 + 10x^2 + 5x - 10
11x^2 + 48x
User Ron Kalian
by
8.2k points
2 votes

Answer:


(x^2+43x+10)-(-10x^2-5x+10)=11x^2+48x

Explanation:

Given polynomial
(x^2+43x+10) \ and \(-10x^2-5x+10)

We have to subtract the given polynomials.

Consider
(x^2+43x+10) \ and \(-10x^2-5x+10)

Subtract (1) - (2) , we have,


(x^2+43x+10)-(-10x^2-5x+10)

rewrite by applying plus-minus rule
-(-a)=a , we have,


x^2+43x+10+10x^2+5x-10

Grouping like terms, (like term are terms with same variable having same degree)


=x^2+10x^2+43x+5x+10-10


\mathrm{Add\:similar\:elements:}\:43x+5x=48x


=x^2+10x^2+48x+10-10


\mathrm{Add\:similar\:elements:}\:x^2+10x^2=11x^2


=11x^2+48x+10-10

Solving , we get,


=11x^2+48x

Thus,
(x^2+43x+10)-(-10x^2-5x+10)=11x^2+48x

User Uzo
by
8.2k points