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A football game starts with a kickoff. If the ball is kicked with a velocity of 72 m/s 35 o to

the horizontal. How far will the football travel? What is the speed an angle of impact?
Explain please

User Pharsfalvi
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2 Answers

7 votes

Final answer:

To determine the distance traveled by the football, we can use the projectile motion equations. We can break down the initial velocity into horizontal and vertical components using the given angle of 35°.

Step-by-step explanation:

To determine the distance traveled by the football, we can use the projectile motion equations. We can break down the initial velocity into horizontal and vertical components using the given angle of 35°. The horizontal component of the velocity is given by vx = v * cos(35°), where v = 72 m/s.

The vertical component of the velocity is given by vy = v * sin(35°). Since the ball starts at ground level, the initial vertical position is 0.

In projectile motion, the horizontal distance traveled (range) is given by R = vx * t, where t is the time of flight. The time of flight is given by t = 2 * vy / g, where g is the acceleration due to gravity (approximately 9.8 m/s²).

Substituting the given values into the equations, we can calculate the distance traveled and the speed and angle of impact at the given time.

User PatDuJour
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6 votes

Answer:

Explanation: very far

User Dewal Tewari
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