Question

Write and solve an inequality for the following: A fish tank can hold at most 315 gallons of water. if a hose is filling the fish tank at a rate of 15 gallons every 10 minutes, how many hours can the hose be left on before the tank overflows?

Answer 1

5 or 6 hours

Explanation:

So the most you can fill up is 315 gallons of water, then 15 gallons every 10 minutes so.... how much times does 10 go into 315 31 and a half times so it would take 32 of those to over fill it. That means we have to convert now, it will be 5 or 6 hours sorry I miss counted try on of those! I hope I could help have a great rest of your day or night!! :))

Answer 2

Step 1

Find the unit rate

`(15)/(10) (gallons)/(minute)= (1.5)/(1) (gallons)/(minute)`

Step 2

Convert
`(gallons)/(minute)` to
`(gallons)/(hour)`

we know that

`1\ hour=60\ minutes`

so

`(1.5)/(1) (gallons)/(minute)=(1.5)/((1/60)) =60*1.5=90(gallons)/(hour)`

Step 3

Find the inequality

Let

x--------> the time in hours

`90x < 315` ------> this is the inequality

Step 4

Solve the inequality

`90x < 315`

Divide by
`90` both sides

`90x/90 < 315/90`

`x < 3.5\ hours`

therefore

the answer is

Hose can be left on before tank overflows less than
`3.5\ hours`