Question

Please help me, someone! 1. For this assessment, explicitly state the five steps of a simulation and carry out the simulation. Use the random digit table.

A basketball player makes 80% of her free throws. Recently during a very close game, she shot 5 free throws near the end of the game and missed 3 of them. The fans booed. What is the probability of her missing 3 (or more) free throws out of 5? Set up and conduct a simulation (using the random digits below) with 10 repetitions.


83234602784360127630126087268768056651093246461081275417450
17491243217468017649817480716408712807408783402746237416207
48648148631085738560871267162622568746587387234879847296948
179846198459812659816512460043380430440

Answer 1

In order to find the probability of the event:
"missing 3 (or more) free throws out of 5" we need to compute three probabilities and add them like this:

`0.2^30.8^2+0.2^40.8+0.2^5=0.00032`
The first term is the probability of missing 3 throws,
The second term is the probability of missing Two ones.
The third term is the probability of missing three ones.