Question

A quadratic function f(x)=ax2 passes through (0,0) and (5,5). write an equation for this function

Answer 1

y = (1/5)x² or y = x²/5

Explanation:

We have the function f(x) = ax² and are given that the point (5,5) is on the parabola. We need to find 'a'. f(x) can be replaced with 'y', so we can rewrite the equation as...

y = ax²

We know that when x = 5, y = 5, so we have

5 = a(5²) now simplify...

5 = 25a

5/25 = a

1/5 = a, so our equation becomes

(1/5)x² or x²/5 (the expressions are equal)