Question

What is the value of x in the equation x^2 + 2 = 0

Answer 1

`{ \tt{ {x}^(2) + 2 = 0 }} \\ \\ { \tt{ {x}^(2) = - 2 }} \\ \\ { \tt{x = √( - 2) }}`

- At this point, we can't operate the square root. Let's introduce the imaginary part of a value

From complex numbers;

`{ \boxed{ \tt{{ \red{note} \: {\rightarrow{i * i = - 1 = {i}^(2) }}}}}}`

Therefore;

`{ \tt{x = \sqrt{2 * {i}^(2) } }} \\ \\ { \boxed{ \rm{ \: x = i √(2) \: \: }}}`