If these are the missing choices:
The ordered pair that is the solution to the system lies in Quadrant I .
The ordered pair that is the solution to the system lies in Quadrant II .
The x-coordinate of the solution is −3 .
The y-coordinate of the solution is 3.
The x-coordinate of the solution is 3.
The y-coordinate of the solution is 4.
Given:
1st equation: 8x + 6y = 48
2nd equation: 2x - 3y = -6
My solution:
We need to zero out one variable to get the value of the other. In this case, we need to multiply the 2nd equation by 4 to zero out variable x.
4(2x – 3y) = 4(-6)
8x – 3y = -24
We then subtract the answer of the 2nd equation from the 1st equation.
8x + 6y = 48
-(8x -3y = -24)
8x + 6y = 48
-8x + 12y = + 24
0 + 18y = 72
y = 72 / 18
y = 4
We then substitute y by its value in the 1st equation to get the value of x.
8x + 6(4) = 48
8x + 24 = 48
8x = 48 – 24
8x = 24
x = 24/8
x = 3
the coordinate point is (3,4).
Of the 6 choices, the following choices are TRUE:
The ordered pair that is the solution to the system lies in Quadrant I .
The x-coordinate of the solution is 3.
The y-coordinate of the solution is 4.