Answer:

Explanation:
Given : Luka has a bag containing 5 socks: 3 red, 1 white, and 1 black.
Then, probability that he first draw a black sock : P(black)

Since we replaced first sock , then the total number of socks in bag remains the same i.e. 5.
Probability that he draw a red sock : P(red)

Since both the events are independent , thus
P(black then red)=P(Black) P(red)

Hence, the probability that he will draw a black sock and then a red sock=
