we are given that
First point as (2,-2)
so, x1=2 , y1=-2
second point as (-3,4)
so, x2=-3 , y2=4
Firstly, we will find slope
![m=(y_2-y_1)/(x_2-x_1)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/25uxp4sblay2143idvgkz738ukrk1vzo5g.png)
now, we can plug values
![m=(4-(-2))/(-3-2)](https://img.qammunity.org/2019/formulas/mathematics/high-school/11g7oog45mtocjcqi19qjl7pau4lq3pqgm.png)
![m=(6)/(-5)](https://img.qammunity.org/2019/formulas/mathematics/high-school/epbvmoznfv489516ey7anizvbofrsbyrus.png)
![m=-(6)/(5)](https://img.qammunity.org/2019/formulas/mathematics/high-school/gvipva3teiri3omkx5teivml1aogkdsfa9.png)
now, we can use point slope form of line
![y-y_1=m(x-x_1)](https://img.qammunity.org/2019/formulas/mathematics/college/lob8zuuisy2ohheuctatxwwco4ukatcrj3.png)
now, we can plug values
and we get
![y+2=-(6)/(5)(x-2)](https://img.qammunity.org/2019/formulas/mathematics/high-school/fts1akcictvezwqqxnsdb9ubq8t1xkxjxw.png)
now, we can solve for y
![y=-(6)/(5)x+(2)/(5)](https://img.qammunity.org/2019/formulas/mathematics/high-school/jl5eksmlhcm9gnuav467l23sjqixdzazri.png)
now, we can plug x=2
![y=-(6)/(5)* 2+(2)/(5)](https://img.qammunity.org/2019/formulas/mathematics/high-school/22tfn4c32mqknqhg921bwkyk7f70h6b48y.png)
![y=-(12)/(5)+(2)/(5)](https://img.qammunity.org/2019/formulas/mathematics/high-school/mss82eov8iywq24hr911pelxuw0r6s2i95.png)
![y=-(10)/(5)](https://img.qammunity.org/2019/formulas/mathematics/high-school/rw2yulo60o80wl7n6nwa53h2nip2tzhomf.png)
.................Answer