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Given △ABC, sin(A) =

A. cos(B)
B. sin(B)
C. cos(C)
D. tan (C)

Given △ABC, sin(A) = A. cos(B) B. sin(B) C. cos(C) D. tan (C)-example-1
User Amad
by
8.8k points

2 Answers

3 votes

the answer is cos(C).

User Mantish
by
7.9k points
7 votes

we know that

In a right triangle ABC

m∠A+m∠C=
90\° -------> by complementary angles

so


sin(A)=cos (C)\\and\\cos(A)=sin (C)

therefore

the answer is the option

C. cos(C)

User Statquant
by
8.7k points

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