Question

GeF3H is formed from GeH4 and GeF4 in the combination reaction: GeH4 + 3GeF4 -> 4GeF3H. If the reactiln yield is 92.6%, how many moles of GeF4 are needed to produce 8 mol of GeF3H?

Answer 1

Answer is: 6,48 mol of GeF₄ are needed.
Chemical reaction: GeH₄ + 3GeF₄ → 4GeF₃H.
n(GeF₃H) = 8 mol.
n(GeF₄) = ?
from chemical reaction: n(GeF₃H) : n(GeF₄) = 4 : 3.
8 mol : n(GeF₄) = 4 : 3.
4n(GeF₄) = 24 mol.
n(GeF₄) = 6 mol ÷ 0,926.
n(GeF₄) = 6,48 mol.

Answer 2

Answer : The number of moles of
`GeF_4` needed to produce 8 mole of
`GeF_3H` are, 6.48 moles.

Explanation :

The given balanced chemical reaction is:

`GeH_4+3GeF_4\rightarrow 4GeF_3H`

First we have to calculate the moles of
`GeF_4`

From the balanced chemical reaction we conclude that,

As, 4 moles of
`GeF_3H` produced from 3 mole of
`GeF_4`

So, 8 moles of
`GeF_3H` produced from
`(8)/(4)* 3=6` mole of
`GeF_4`

Now we have to calculate the moles of
`GeF_4` when the reaction yield is 92.6 %.

As, 92.6 % yield produced from 6 moles of
`GeF_4`

So, 100 % yield produced from
`(100\%)/(92.6\%)* 6=6.48` moles of
`GeF_4`

Therefore, the number of moles of
`GeF_4` needed to produce 8 mole of
`GeF_3H` are, 6.48 moles.